5b^2+28b-12=0

Solution for 5b^2+28b-12=0 equation:

Simplifying
5b2 + 28b + -12 = 0

Reorder the terms:
-12 + 28b + 5b2 = 0

Solving
-12 + 28b + 5b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(-6 + -1b)(2 + -5b) = 0

Subproblem 1
Set the factor '(-6 + -1b)' equal to zero and attempt to solve:

Simplifying
-6 + -1b = 0

Solving
-6 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '6' to each side of the equation.
-6 + 6 + -1b = 0 + 6

Combine like terms: -6 + 6 = 0
0 + -1b = 0 + 6
-1b = 0 + 6

Combine like terms: 0 + 6 = 6
-1b = 6

Divide each side by '-1'.
b = -6

Simplifying
b = -6
Subproblem 2
Set the factor '(2 + -5b)' equal to zero and attempt to solve:

Simplifying
2 + -5b = 0

Solving
2 + -5b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -5b = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -5b = 0 + -2
-5b = 0 + -2

Combine like terms: 0 + -2 = -2
-5b = -2

Divide each side by '-5'.
b = 0.4

Simplifying
b = 0.4
Solution
b = {-6, 0.4}